As moon passes overhead, high tide (one of two high tides a day) will come after a short delay. But why ? Why is seawater with a low specific gravity bulged ? Newton imagined that moon will continue falling. Earth will continue falling also. And seawater will cotinue falling too. So, it doesn’t matter how specific gravity is.

]]>Allow me to rewrite again.

Moon and earth are supposed to be two-body problem. Also it is supposed that the common center of gravity of moon and earth is situated outside the earth. And the orbit of earth is a perfect circle, and earth is a perfect sphere. In the illustration, the surface of earth closest to moon is A and the surface farthest from moon is B. At the two points A and B, the strength of resultant forces of moon’s gravity and centrifugal force (of earth) will be the same (act to opposite directions). Otherwise, earth cannot stay on orbit of perfect circle. This will explain that the level of high tide twice a day are the same.

]]>Allow me to rewrite again.

Moon and earth are supposed to be two-body problem. Also it is supposed that the common center of gravity of moon and earth is situated outside the earth. And the orbit of earth is a perfect circle, and earth is a perfect sphere. In the illustration, the surface of earth closest to moon is A and the surface farthest from moon is B. At the two points A and B, the strength of resultant forces of moon’s gravity and centrifugal force (of earth) will be the same (act to opposite directions). Otherwise, earth cannot stay on orbit of perfect circle. This will explain that the level of high tide twice a day are the same.

]]>Suppose the moon and the earth is two-body problem. And imagine, the earth is rotating (revolving) around the common center of gravity with the moon. The orbit is a perfect circle. If lunar attractive force acting on the center of gravity of the earth is action, the centrifugal force of the earth is a reaction. And the strength of the two will be equal. This will be also true for the earth as a whole.

In an illustration, the earth is drawn next to moon. Imagine two points on the surface of the earth closest to the moon and farthest from the moon. The difference between lunar attractive force and the centrifugal force of the earth at above two points will be almost equal and therefore the resultant force will also be almost equal. This will explain that the level of high tides twice a day are almost equal.

Note: Is the law of action and reaction valid for celestial bodies on elliptical orbits?

]]>Mercury is moving on the revolution orbit. The sun’s gravity is equal to the centrifugal force. Because the two are action and reaction. Following are some explanations. Centrifugal force follows Mercury’s mass. But in addition, gravity is affected by the size of Mercury (and acting position of gravity is different). These are caused by the non-uniformity of gravity (in the space occupied by Mercury). And after perihelion passage, orbit will be pulled inward (from its original orbit).

High tide level twice a day is the same. Gravity and centrifugal force caused by the moon will be action and reaction. Centrifugal force is not fictitious.

]]>In Mercury (in terms of Mercury’s size), the non-uniformity of the Sun’s gravity may be the main cause of

perihelion shift. In artificial satellites, the effects of non-uniformity of the Earth’s gravity (the position of the center of mass and the center of gravity are different) are also mentioned.

Bradley found annual aberration on gamma star : Eltanin. In books, picture of ellipse is shown. However, this ellipse must be warped because of secular aberration (not only Eltanin). With this warp, the motion of solar system relative to aether must be clarified.

Light emitted from a source in outer space will follow the emission theory. But for a few seconds only. The corner cube settled on the surface of the moon proves this.

The motion of an observer relative to light waves is the same as the motion of an observer relative to sound waves. Light waves are light waves. An observer is an observer. And everything follows Galilean transformation.

The speed of light in medium is c/n. The MM experiment (done in air) is nonsense.

]]>Suppose that Mercury revolving is devided in two (hemisphere facing the sun A and the other B). Main forces acting on the two are gravity of the sun and inertial force (centrifugal force). Inertial force is A＜B and gravity of the sun is A＞B.

Yes, each force acting on the outside and inside is different. Inertial force pulls the orbit to the outside. But actual orbit of Mercury is pulled to the inside. Gravity of the sun acting on the two is inversely proportional to the square of the distance (not come out even. not plus minus zero). In Mercury, the action of gravity will be superior.

]]>Let’s reconsider the main cause of perihelion shift again. On Mercury or Venus, main cause will be the size of sphere. On Earth or Mars, effect of satellite is added. On asteroids each, effects of size is negligible. On Jupiter or Saturn each, the powerful and unstable effect of the other will act. On Uranus or Neptune each, slight and unstable effect of the other all planets will act. Anyway, common view on Mercury is wrong.

P.S. Sorry, I can not receive E mail. I do not have PC.

]]>This is the top of tall tower. Two rods of equal mass and different length are arranged vertically (heigth of center of gravity is the same). Now, two rods start to fall at the same time. The fall of center of gravity will not be the same. Because the strength of gravity is inversely proportional to the square of the distance. This will be the main cause for perihelion shift of Mercury.

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